Purpose: To discover at what mass to volume ratio magnesium is converted to hydrogen.
Data:
| 1 m of Magnesium | 1.5 g |
| Pressure (?) | 30.04” |
| Magnesium Length | About 3.0 cm |
| Temperature of Water | 21°C |
| mL H2 | 49.25 mL |
Calculations:
1) Weight of Mg is 0.000045 g, or .045 mg
2) About 0.0011 moles of Mg were used
3) If the total pressure of the water vapor in the tube is 30.04 kPa, and the total pressure of gas in the tube is 101.3 kPa, then the partial pressure of hydrogen gas in the tube must be 101.3 - 30.04 = 71.26 kPa.
4) If the ideal gas law is PV = nRT, then the ideal gas pressure of hydrogen can be calculated as 101.3xV = .0011x.821x273, which is 0.0024 mL.
5) The volume of hydrogen gas that would be produced by a mole of magnesium reacting with an excess of HCl would be 44772.72 mL, or 44.77 L of hydrogen gas.
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